Question

2x^2+7x-9=0.Решить уравнения

Answer 1

$2 x^{2} +7x-9=0 \\ D=49+72=121 \\ \sqrt{D} =11 \\ x_{1} = \frac{-7+11}{4} = \frac{4}{4} =1 \\ x_{2} = \frac{-7-11}{4} =- \frac{18}{4} =-4.5$