Question

Найти корни уравнения 2х^2-13х-7=0

Answer 1

 2х²-13х-7=0

D=169+56=225

x₁=(13+15)/4 = 7

x₂=(13-15)/4=-1/2

Answer 2

$2x^2-13x-7=0\ D=b^2-4ac=169-4*2*(-7)=225\ x1=frac{-b+sqrt{D}}{2a}=frac{13+15}{2*2}=7 x2=frac{-b-sqrt{D}}{2a}=frac{13-15}{4}=-frac{1}{2}$