Предмет: Химия, автор: Oocheneeq

Термохимическое уравнение реакции горения ацетилена C2H2 + 2 1\2 O2 = 2CO2 + H2O +1299,63 кДж
Какое кол-во теплоты выделится, если в реакцию вступит ацителлена:
а) 33,6л
б) 0,2 моль
в) 6.5г

Сколько было израсходовано ацетилена, если выделилось 324,9 кДж теплоты?

Ответы

Автор ответа: Анетка125

1

n(C2H2)=33.6/22.4=1.5моль9кДж
Q=1.5*1299.63=1949.45моль

Q=0.2*1299.63=259.939кДж

n(C2H2)=6.5/26=0.25моль
Q=0.25*1299.63=324.9кДж

n(C2H2)=324.9/1299.63=0.25моль
V(C2H2)=0.25*22.4=5.6л

Oocheneeq: Еще раз благодарю! Очень сильно выручаете! Последняя просьба и я откланиваюсь с этого сайта: http://znanija.com/task/12384697 и http://znanija.com/task/12384662

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