Предмет: Физика, автор: Слава2281

камень обьёмом 0,2м находится в воде .чему равна выталкивающая сила действующая на него

Ответы

Автор ответа: TequilaSunrise

Дано:
V=0,2 м3
Р(плотность) воды= 1000 кг/м3
Найти: F арх=?
Решение:
F арх =p(плотность жидкости)*g*v(объем)
Подставим значения:
p-1000 кг/м3
g=10 н/кг
v=0.2 м3
1000*10*0.2= 2000 Н = 2 кН

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