Question

Помогите
$\int\limits \, dx /(1-6x)^2$

Answer 1

=S (1-6x)⁻² dx=(1-6x)⁻²⁺¹/(-6*(-2+1))+C=(1-6x)⁻¹/6+C=1/(6*(1-6x)) +C=1/(6-36x)+C