Question

Разложить на множители xy+3y+xz+3z
4. 25–c²
5.ab²–2abc+ac²

Answer 1

xy+3y+xz+3z=(xy+xz)+(3y+3z)=x(y+z)+3(y+z)=(y+z)(x+3)
$25- c^{2} = 5^{2} - c^{2} =(5-c)(5+c)$
$a b^{2} -2abc+a c^{2} =a( b^{2} -2bc+ c^{2} )=a (b-c)^{2} =a(b-c)(b-c)$