Question

-$x^{2}$+12x-35$\leq$0

Answer 1

х²+12х-35≤0
х²+12х-35=0
Д=144+4*35=144+140=284
х₁=-12-√284 = -12 -2√71 = -6 -√71
           2              2
х₂=-6 + √71
     +                     -                        +
-------- -6-√71 ------------ -6 +√71 --------------
                   \\\\\\\\\\\\\\\\\
х∈[-6-√71; -6+√71]