Предмет: Геометрия, автор: юлч1

Більша діагональ ромба дорівнює 12√3 см,а один з його кутів - 120°.Знайдіть сторону і меншу діагональ

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Автор ответа: myrchuk

5

Більша діагональ D = а √2 - 2 · косінус β, звідси сторона
а = D / √2 - 2 ·косінусβ = 12√3 / √2 - 2 · косінус 120 = 12√3 / √3 = 12

Менша діагональ d = а √2 + 2 · косінусβ = 12 · √2 + 2 · (- 1/2) = 12 · √ 2-1 = 12

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