Question

y= корень(1-sinx\cosx), x0=$\pi$\4

Answer 1

y(x) =√(1-sinx/cosx) , xo =π/4.
y(xo) =  y(π/4)=√(1-sin(π/4)/cos(π/4))  =√(1 - (1/√2)/(1/√2)) =√(1 - 1) = 0 .