Question

2/3x+1 -x/1-3x =2x/9x^2-1

Answer 1

 $\\\frac{2}{3x+1} - \frac{x}{1-3x} = \frac{2x}{9x^2-1} \\ \\\frac{2}{3x+1} - \frac{x}{1-3x} = \frac{2x}{(3x-1)(3x+1)} \\ \\\frac{2}{3x+1} + \frac{x}{3x-1} = \frac{2x}{(3x-1)(3x+1)} \\\\ 2(3x-1)+x(3x+1)=2x \\ 6x-2+3x^2+x-2x=0 \\ 3x^2+5x-2=0 \\\\ x_1=\frac{-6}{3}=-2$

$x_2 \neq \frac{1}{3}$ - посторонний корень.