Question

Решите систему уравнений х+3у=13 и 6у-2х=-2

Answer 1

$\left \{ {{x+3y=13} \atop {6y-2x=-2}} \right. \\ \\ \left \{ {{x+3y=13} \atop {2(3y-x)=-2}} \right. \\ \\ \left \{ {{x+3y=13} \atop {3y-x=-1}} \right. \\ 3y=13-x \\ \\ 13-x-x=-1 \\ -2x=-13-1 \\ -2x=-14 \\ x=7 \\ \\ 3y=13-7 \\ 3y=6 \\ y=2$