Предмет: Алгебра, автор: RESPECTT

Разложить на множители 15m^3n^2p-35p^2nq^3+25mn^3q^2-21m^2p^3q

Ответы

Автор ответа: m11m

5

15m³n²p - 35p²nq³ +25mn³q² - 21m²p³q=

=(15m³n²p+25mn³q²)-(35p²nq³+21m²p³q)=

=5mn²(3m²p+5nq²) - 7p²q(5nq²+3m²p)=

=(3m²p+5nq²)(5mn²-7p²q)

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