Question

$cos^{3}xsinx-sin^{3}cosx=frac{1}{8}$

Answer 1

cosxsinx(cos^2x - sin^2x) = 1/8

2cosxsinx(cos^2x - sin^2x) = 1/4

sin2x*cos2x = 1/4

2sin2x*cos2x = 1/2

sin4x = 1/2

4x = П/6 + 2Пk       4x = 5П/6 + 2Пk

x = П/24 + Пk/2        x = 5П/24 + Пk/2