Question

Решите уравнение
√12-√48
-------------- =
√108+√3

Answer 1

$-\sqrt{6}$

Answer 2

$\frac{ \sqrt{12} - \sqrt{48} }{ \sqrt{108} + \sqrt{3} } = \frac{ \sqrt{4*3} - \sqrt{16*3} }{ \sqrt{36*3} + \sqrt{3} } = \frac{ 2\sqrt{3} - 4\sqrt{3} }{ 6\sqrt{3} + \sqrt{3} } = \frac{-2 \sqrt{3} }{7 \sqrt{3} } =- \frac{2}{7}$