Предмет: Химия, автор: Аноним

Вычислите концентрацию соляной кислоты, образовавшейся при растворении 56 литров хлороводорода из 100 граммах воды


MailaMiller: Ответ к задаче есть? У меня получилось 47,7 %.

Ответы

Автор ответа: MailaMiller
2
Дано:
V (HCl) = 56 л ;
m (H₂O) = 100 г.
Найти:
ω (HCl) – ?
Решение:
n (HCl) = 56 л : 22,4 л/моль = 2,5 (моль).
m (HCl) = 2,5 моль · 36,5 г/моль = 91,25 (г).
91,25 г + 100 г = 191,25 (г) – масса раствора.
191,25 г – 100 %
91,25 г – х %
     91,25 · 100
х =   191,25     = 47,7 (%) – концентрация HCl.
Ответ: 47,7 %.
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