Предмет: Алгебра, автор: maral09

дано F(x)=4sin52x надо найти F’(π8)

Ответы

Автор ответа: fuflunce

F(x)=4sin52x

F'(x) = 4cos(52x)*52 = 208cos(52x)

F'(π/8) = 208cos(52*π/8) = 208cos(6,5π) = 208cos(π/2) = 208*0 = 0

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