Question

решите систему
12x+3y-9=2x+10
8x+20=10+2(3x+2y)

Answer 1

12х-2х+3y-9-10=0
10x+3y-19=0
8x+20=10+6x+4y
8x-6x-4y+20-10=0
2x-4y+10=0

Answer 2

= система
12х+3у-2-9-10=0
8х+20=10+6х+4у <=>

10х+3у-19=0
8х-6х-4у+20-10=0 <=>

10х+3у-19=0
2х-4у+10=0 <=>

2х=4у-10
10у+3у-19=0 =>

х=2у-5
10 (2у-5)+3у-19=0

х=2у-5
20у-50+3у-19=0

х=2у-50
23у-69=0

23у=69
х=2у-50

х=3
х=1