Предмет: Химия, автор: Аноним

какой обЪем при нормальных условиях займут, 6,02*10 в 29 степени молекул водорода

Ответы

Автор ответа: psv68

найдем количество вещества водорода n=n(молекул)/Na , где Na-постоянная Авогадро =6,022*10^23 1/моль

n=6.02*10^29/6.02*10^23=1*10^6 моль

V=n*Vm=1*10^6моль*22.4л/моль=22,4*10^6л=22,4*10^3м3

Ответ 22,4*10^3 м3

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