Question

Вариант1 упр 2 помогите

Answer 1

$\frac{2,4x-1,26}{ \frac{1}{6} } = \frac{1,3x-0,5}{ -\frac{1}{90} } \\ - \frac{1}{90} *(2,4x-1,26)= \frac{1}{6}*(1,3x-0,5) \\ - \frac{2}{75} x+ \frac{7}{500} = \frac{13}{60} x- \frac{1}{12} \\ \frac{13}{60}x+ \frac{2}{75}x= \frac{7}{500}+ \frac{1}{12} \\ \frac{73}{300}x= \frac{73}{750} \\ x= \frac{73}{750}* \frac{300}{73} \\ x= \frac{2}{5} =0,4$