Question

(sinx+tgx/cosx+1)всё в квадрате и +1

Answer 1

$(frac{sinx+tgx}{cosx+1})^{2}+1=(frac{sinx+frac{sinx}{cosx}}{cosx+1})^{2}+1=(frac{frac{sinxcosx+sinx}{cosx}}{cosx+1})^{2}+1=$

 

$=(frac{sinx(cosx+1)}{cosx(cosx+1)})^{2}+1=tg^{2}x+1$