Предмет: Алгебра, автор: bosskaa

Помогите !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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Автор ответа: Latac
1
Уравнение имеет два различных корня при D>0, значит, b^2-4ac>0, (6p)^2-4*1*9>0, 36p^2-36>0, p^2-1>0, p^2>1. Пусть p^2=1, тогда р=±√1, р1=-1, р2=1. Далее смотри рисунок и опять решение. р∈(-∞;-1)и(1;+∞).
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