Предмет: Математика, автор: Юра1234

Із точки А до площини проведено похилі АВ та АС та перпендикуляр АО.
Знайти: ВО і АС,якщо ВО + АС = 3 (см), АВ = $\sqrt{3}$ (см), ОС = $\sqrt{2}$ (см)

Ответы

Автор ответа: Sherlocked13

Нехай АС=х, ВО=у
Х+у=3
^3*^3-у*у=х*х-^2*^2
Х=3-у
3-у2=9-6у-у2-2
6у=4
у=2/3
Х=7/3

Юра1234: 3 та 5 рядки не зрозуміло(

Sherlocked13: ^-корінь з числа. трикутники АОВ і АОС мають спільну строону, яка за теоремою Піфагора знаходиться за допомогою рівності із кожних двох сторін трикутників. а у п'ятому підставила із АС+ВО=3 значення ікса, щоб спростити рівняння і прибрати одну змінну

Юра1234: тобто 3 рядок буде звучати: корінь з 3 помножити н корінь з 3-у помножити на у = х помножити на х - корінь з два помножити на корінь з два?
а 5 рядок: 2 - 2у = 9-6у - 2у - 2?

Sherlocked13: так

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