Предмет: Математика, автор: рполдролд

Задайте формулой линейную функцию, если известно, что её график проходит через точку А(1;-2) и параллен: биссектрисе второго и четвёртого координатных углов.

Ответы

Автор ответа: kirichekov

биссектриса II и IV координатных углов линейная функция: у=-х
формула линейной функции у=кх+в
по условию прямые параллельны, следовательно к=-1
у=-х+в
А(1;-2)
-2=-(-1)+в, в=-1
у=-х-1 линейная функция, график которой параллелен прямой у=-х (биссектрисе II и IV координатных углов)

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