Question

4t(t+3)-2t(2t+1) разложить на множители

Answer 1

$4t(t+3)-2t(2t+1)=4 t^{2}+12t-4 t^{2} -2t= 10t$

Answer 2

4t(t+3)-2t(2t+1)=4t^2+12t-4t^2-2t
12t-2t=2(10t-t)