Предмет: Алгебра, автор: ksenzabolotski

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Автор ответа: ЗолотойКот
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 \frac{x^2}{6y^5}- \frac{x}{3y^6} = \frac{x^2y}{6y^6}- \frac{2x}{6y^6}  = \frac{x(xy-2)}{6y^6}
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