Question

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Answer 1

1)a) $2-(1 \frac{11}{30} -1,7)*1 \frac{2}{7} :1 \frac{13}{14} =2-( \frac{41}{30}- \frac{17}{10} )* \frac{9}{7} * \frac{14}{27} =2-( \frac{41-51}{30} * \frac{2}{3}$$=2+ \frac{10}{30} * \frac{2}{3} =2+ \frac{2}{9} = \frac{18+2}{9} = \frac{20}{9} = 2\frac{2}{9}$
б)$(-1 \frac{2}{3})^3*(-0,75)^2*(-0,024)=(- \frac{5}{3} )^3*(- \frac{75}{100} )^2*(- \frac{24}{1000})=\frac{-125}{27}$$*( \frac{3}{4} )^2*(- \frac{3}{125} )= \frac{1}{16}$
2.$= \frac{7}{9} ( \frac{18}{10} a- \frac{27}{10} )+ \frac{6}{10} (2-3a)= \frac{7}{9} * \frac{18a}{10} - \frac{7}{9} * \frac{27}{10} + \frac{6}{10}*2 - \frac{6}{10} *3a=$$\frac{7}{5} a- \frac{21}{10} + \frac{6}{5} - \frac{9}{5} a= \frac{16}{5} a+ \frac{-21+12}{10} =- \frac{9}{10}$