Предмет: Алгебра, автор: dekha3327328

срочно (график линейных функции пересекает оси координаты точках "-6;0" и "0;7" задайте эту функцию формулой

Ответы

Автор ответа: kirichekov

1

у=кх+в
А(-6;0). В(0;7). в=6
0=к*(-6)+7
к=7/6
у=(7/6)*х+7

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