Question

(x-4)²-25x² срочно помогите

Answer 1

$(x-4)^{2} -25 x^{2} =0 \\ x^{2} -8x+16-25 x^{2} =0 \\ -24 x^{2} -8x+16=0 \\ 24 x^{2} +8x-16=0 \\ D=64-4*24*(-16)=1600=40 ^{2} \\ x= \frac{-8+40}{48} = \frac{32}{48} = \frac{4}{6} \\ x= \frac{-8-40}{48} =1$