Question

log(1.8 )5+ log1.8 (1/9)

Answer 1

$log_{1,8}5+log_{1,8}(\frac{1}{9})=log_{\frac{9}{5}}(\frac{5}{9})=-1$

Answer 2

$log_{ \frac{9}{5}} 5* \frac{1}{9} = log_{ \frac{9}{5}} \frac{5}{9}=-1*log_{ \frac{9}{5}} \frac{9}{5} =-1*1=-1$