Предмет: Физика, автор: malishka15551

помогите с задачкой пожалуйста.
В вертикальном однородном магнитном поле на двух тонких нитях подвешен горизонтально проводник длиной 0,32 м, сила тяжести которого 0,25 Н. Определить индукцию магнитного поля, при которой нити с вертикалью образуют угол 45° при силе тока в проводнике 1,25 А.

Ответы

Автор ответа: Pewuu

Т*sina=mg
T*cosa= F(a)
F(a)=B I l
tga=mg/B I L
tga= 20.4*10³*10/ 0.5*0.2*2=1.02*10²
a=arctg102=89.4⁰

malishka15551: спасибо большое!

malishka15551: с ответом не сошлось, в учебнике 625 мТл

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