Предмет: Геометрия, автор: ifdel

В прямоугольнике одна сторона равна 6, а диагональ равна 10. Найдите площадь

Ответы

Автор ответа: axe211

Если это прямоугольный треугольник, то S=1/2a*b , где a и b - катеты.

c^2=a^2+b^2, где с - это гипотенуза.

Найдём b:
b= $\sqrt{c^2-a^2}$
b= $\sqrt{100-36}$ =8
S=1/2*8*6=24

ifdel: нет это прямоугольник

axe211: ок, тогда так s=a*b. A и B мы нашли. S=8*6=48

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