Предмет: Математика, автор: 89841753052

расстояние между линейным кораблём и фрегатом равно 130 км.и капитаны получили приказ об одновременном начале движения на встречу друг км другу и встрече через 2 часа с какой скоростью должно двигаться каждое судно если скорость линейного корабля меньше чем фрегата на 50 км в час

Ответы

Автор ответа: рашид00000
1
1) 130:2=65(км/час) скорость сближения корабля с фрегатом                            2) (65-50):2=15:2=7,5(км/час скорость корабля                                                   3) 50+7,5=57,5(км/час) скорость фрегата                                                              Ответ: Лодка движется со скоростью 7,5(км/час), фрегат со скоростью 57,5(км/час)

89841753052: спасибо
89841753052: а это точно правильно
рашид00000: да, сами посчитайте... через 2 часа должны встретиться. 57,5*2=115(км) пройдет фрегат, 7,5*2=15 (км) пройдет лодка.... расстояние 130(км) 115+15=130(км) расстояния пройдут за 2 часа...это уже проверка и объяснение в одном лице...
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