Предмет: Геометрия, автор: missbogun2013

Из точки А, которая находится на расстоянии 5 см от плоскости α, проведена наклонная АВ. Найдите ее длину, если ее проекция равна 3 см. помогите, пожалуйста!

Ответы

Автор ответа: tanya2512

Прямоугольный ΔАВН, у которого катет АН (расстояние до плоскости)=5см,
катет НВ (проекция наклонной)=3 см и гипотенуза АВ(наклонная).
АВ²=АН²+НВ²=5²+3²=34
АВ=√34

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