Question

Уравнение: (sin (3x/2)+ cos(3x2))^2=12

Answer 1

 (sin (3x/2)+ cos(3x2))^2=12

sin^2(3x/2)+2sin3x/2cos3x/2+cos^2(3x/2)=1/2

1+sin3x=1/2

sin3x=-1/2

3x=(-1)^(n+1)*pi/6+pi n

x=(-1)^(n+1)*pi/18+1/3pi n