Question

Помогите,пожалуйста))

Answer 1

cos(π+β)*sin(3π/2+β) - ctg(β-π)*ctg(3π/2 - β) = 
-cosβ*(-cosβ) - ctgβ*tgβ = cos²β - 1 = - sin²β

sin(3π/2-α)*cos(π-α) + sin(3π-α)*cos(π/2 - α) + tg(π-α)*tg(3π/2+α)=
= -cosα*(-cosα) + sinα*sinα+(-tgα)*(-ctgα) = cos²α+sin²α+1=1+1=2

sin240 * cos(-330) * tg(-315) ctg240 =-√3/2*√3/2*1*1/√3 = -√3/4