Question

4А.03(б), 4А.04(б),4А.06(б)
пожалуйста

Answer 1

$5.4(3y-2)-7.2(2y-3)=1.2 \ 16.2y-10.8-14.4y+21.6=1.2 \ 1.8y=-9.6 \ y=- frac{9.6}{1.8} =- frac{96}{18} =- frac{16}{3} =-5 frac{1}{3}$

$5+ frac{7x-12}{3} =x+13 \ frac{7x-12}{3} =x+8 \ 7x-12=3x+24 \ 4x=36 \ x=9$

$frac{10.5}{y-3.6} = frac{5.1}{y+1.8} \ 10.5(y+1.8) = 5.1(y-3.6) \ 105(y+1.8) =51(y-3.6) \ 35(y+1.8) =17(y-3.6) \ 35y+63=17y-61.2 \ 18y=-124.2 \ y=-6.9$