Question

2-3(2у+1)=15
3х+у+3у=2у-2

Answer 1

$begin{cases}2-3(2y+1)=15\3x+y+3y=2y-2end{cases}Rightarrowbegin{cases}2-6y-3=15\3x+2y=-2end{cases}Rightarrow\Rightarrowbegin{cases}-6y=16\3x+2y=-2;times3end{cases}Rightarrowbegin{cases}-6y=16\9x+6y-6y=-6+16end{cases}Rightarrow\Rightarrowbegin{cases}y=-frac{16}6\9x=10end{cases}Rightarrowbegin{cases}y=-2frac23\x=1frac19end{cases}$