Предмет: Химия, автор: lyashko76

13г цинка растворили в разбавленной хлоридной кислоте. Какой объем водорода выделился при этом?

Ответы

Автор ответа: Senpoliya

13 г    х л
Zn + 2HCl = ZnCl₂ + H₂↑
1 моль   1 моль
65 г/моль    22,4 л/моль

V(H₂) = (13 г * 22,4 л/моль * 1 моль) : (65 г/моль * 1 моль) = 4,48 л

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