Предмет: Физика, автор: Kate9o9

стрела массой 20г. выпущена из лука вертикально вверх с начальной скоростью 20 м/с.Определите кинетическую энергию на высоте 15 м.

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Автор ответа: zzzziga

0

Eп. = mgh = 10*0.02*15 = 3Дж.

Eк. = mV^2/2 = 0.02*20^2/2 = 4Дж.

4 - 3 = 1Дж.

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