Question

корень из 10-х-х в квадрате = х+ 1

Answer 1

$sqrt{10-x-x^2}=x+1$

$10-x-x^2=(x+1)^2$

$10-x-x^2 = x^2+2x+1$

$2<var> x^2+3x-9=0</var>$

$D=9+72=81$

$x1=1,5$

$x2=-3$