Question

a+8/a^2:a+8/a^2-a при а = -0,8

Answer 1

$\frac{a+8}{a^2} : \frac{a+8}{a^2-a} = \frac{a+8}{a^2} * \frac{a(a-1)} {a+8}= \frac{a-1}{a} = \frac{-0,8-1}{-0,8} = \frac{-1,8}{-0,8} = \frac{9}{4} =2 \frac{1}{4}$