Question

Сделать подробно буквы: б,г. Задание во вложении.

Answer 1

$f(x)=x-4 \sqrt{x} \\\ f'(x)=1- \frac{4}{2 \sqrt{x} }=1- \frac{2}{ \sqrt{x} } \\\ f'(0.01)=1- \frac{2}{ \sqrt{0.01} }=1- \frac{2}{0.1 }=-19 \\\ f'(4)=1- \frac{2}{ \sqrt{4} }=1- \frac{2}{2 }=0$

$f(x)= \frac{3-x}{2+x} \\\ f'(x)= \frac{(3-x)'(2+x)-(3-x)(2+x)'}{(2+x)^2} =\frac{-(2+x)-(3-x)}{(2+x)^2} =\frac{-2-x-3+x}{(2+x)^2} = \frac{-5}{(2+x)^2} \\\ f'(-3)= \frac{-5}{(2-3)^2} = \frac{-5}{1} =-5 \\\ f'(-3)= \frac{-5}{(2+0)^2} = \frac{-5}{4} =-1.25$