Question

13-3.6×(4x-4целых7/12)=5/6×(4-11x)

Answer 1

$13-3.6*(4x-4 \frac{7}{12} )=5/6*(4-11x) \\ 13 - 14,4x+ \frac{3,6*55}{12} = \frac{20}{6} - \frac{55}{6} x \\ 13+16,5-14,4x+ \frac{55}{6} x=\frac{20}{6} \\ - \frac{144}{10}x + \frac{55}{6} x=\frac{20}{6}-29,5 \\ \\ - \frac{432}{30}x+ \frac{275}{30}x = \frac{100}{300} - \frac{885}{30} \\ \\ -\frac{157}{30}x =- \frac{785}{30} \\ x=\frac{785*30}{30*157} \\ x=5$