Question

Помогите пожалуйста!!!

Answer 1

$\frac{6-4 \sqrt{2}}{ \sqrt{2}-1}-2 \sqrt{2}= \frac{6-4 \sqrt{2}-2 \sqrt{2}*(\sqrt{2}-1)}{\sqrt{2}-1}=\frac{6-4 \sqrt{2}-4+2 \sqrt{2}}{\sqrt{2}-1}=\frac{2-2\sqrt{2}}{\sqrt{2}-1}=\frac{2(1-\sqrt{2})}{\sqrt{2}-1} \\ =\frac{-2(\sqrt{2}-1)}{\sqrt{2}-1}=-2$