Question

-x^2-10x-23=0 помогите пожалуйста

Answer 1

$-x^{2}-10x-23=0 \\ x^{2}+10x+23=0 \\ D=10^{2}-4*1*23=100-92 =8 \\ x_{1}= \frac{-10- \sqrt{8} }{2} = \frac{-10- \sqrt{4*2} }{2} =\frac{-10- 2\sqrt{2} }{2} =\frac{2(-5-\sqrt{2}) }{2} =-5-\sqrt{2} \\ x_{2}= \frac{-10+ \sqrt{8} }{2} = \frac{-10+ \sqrt{4*2} }{2} =\frac{-10-+2\sqrt{2} }{2} =\frac{2(-5+\sqrt{2}) }{2} =\sqrt{2} -5$