Question

18x = 15x-2 (полоска дроби) х , найти корни

Answer 1

$18x= \frac{15x-2}{x} \\ 18 x^{2} -15x+2=0 \\ D=(-15)^{2}-4*18*2=225-144=81=9^{2} \\ x_{1}= \frac{-(-15)- \sqrt{81} }{2*18} = \frac{15-9}{36} = \frac{6}{36} = \frac{1}{6} \\ x_{2}= \frac{-(-15)+\sqrt{81} }{36} = \frac{15+9}{36} = \frac{24}{36} = \frac{2}{3}$