Question

(y-12)+20=40
Решите плиз уравнения:
(a+6)*3=60
(20+m):2=26
(45-n)*3=12*2
(160+х)-40=300
225:(c+5)=15

Answer 1

(y-12)+20=40
y-12=40-20
y-12=20
y=20+12
y=32

(a+6)*3=60
a+6=60/3
a+6=20
a=20-6
a=14

(20+m)/2=26
20+m=26*2
20+m=52
m=52-20
m=32

(45-n)*3=12*2
45-n=24*3
45-n=72
n=72-45
n=27

(160+x)-40=300
160+x=300+40
x=340-160
x=180

225/(c+5)=15
c+5=15*225
c=3375-5
c=3370