Question

решите уравнение (4-х)^2-12=x(x-3)

Answer 1

(4-x)^2-12=x(x-3)
4^2-2*4*x+x^2-12=x^2-3x
16-8x+x^2-12=x^2-3x
-8x=3x=12-16
-5x=-4
x=-4\-5