Question

х$x^{2}$ +5х-14 $} \geq$ 0

Answer 1

$x^{2}+5x-14 \geq 0\\ x^{2}+5x-14=0\\ x_{1}+x_{2}=-5;\space x_{1}x_{2}=-14\\ x_{1}=-7;\space x_{2}=2\\ x \in (-\infty;-7]\cup[2;+\infty)$

Answer 2

x²+5x-14≥0
x1+x2=-5 U x1*x2=-14
x1=-7 U x2=2
x∈(-∞;-7] U [2;∞)