Предмет: Физика, автор: pavlov12

С какой силой тело объёмом 5 децеметров кубических будет выталкиваться из ртути.

Ответы

Автор ответа: kirills1

FA = p * g * V

p - плотность ( для ртути 13600 кг / м³ )
g - ускорение свободного падения ( 10 Н / кг )
V - объём ( 5 дм³ = 0,005 м³ )

FA = 13600 * 10 * 0,005 = 680 H

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